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If you find that the hydrogen alpha line in a star’s spectrum occurs at a wavelength of 656.45 nm, what is the star’s approximate radial velocity? Note that the rest wavelength of this line is 656.30 nm.

Respuesta :

Answer:

The answer to the question is

The star’s approximate radial velocity is 68.52 km/s

Explanation:

To solve the

The formula is

[tex]\frac{\lambda-\lambda_{rw}}{\lambda_{rw}} = \frac{v_r}{c}[/tex] where

[tex]v_r[/tex] = velocity of the star

λ = Star's spectrum wavelength = 656.45 nm

[tex]\lambda_{rw}[/tex] = Rest wavelength = 656.30 nm

c = Speed of light = 299 792 458 m / s

Therefore we have

[tex]\frac{656.45-656.30}{656.30} =\frac{v_r}{299 792 458}[/tex] or [tex]v_r[/tex] = 68518.7699 m/s or 68.52 km/s

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