mackmariah34 mackmariah34
  • 03-04-2020
  • Mathematics
contestada

Find the perimeter of the shape given length = x^2+4 and the width = 3x-4.Explain how you found your answer to problem .

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opudodennis
opudodennis opudodennis
  • 09-04-2020

Answer:

[tex]2x^{2}+6x[/tex]

Step-by-step explanation:

Perimeter is the distance all round a figure. Given length and width only, then this shale is likely to be a triangle. For a triangle, the area is given by

P=2(l+w)

Where l is the length and w is width.

Substituting w with 3x-4 and l with [tex]x^{2}+4[/tex]

then

[tex]P=2( x^{2}+4 +3x-4)=2( x^{2}+3x)=2x^{2}+6x[/tex]

Therefore, perimeter is [tex]2x^{2}+6x[/tex]

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