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1. A person weighing 1200 N is supported on an inflated air pillow. The total area of the soles of his shoes is 0.1 m². Calculate the minimum pressure of the air inside the pillow. ​

Respuesta :

ujalakhan18

Answer:

[tex]\huge\boxed{\sf P = 12,000 \ Pa}[/tex]

Explanation:

Given:

Force = F = 1200 N

Area = A = 0.1 m²

Required:

Pressure = P = ?

Formula:

[tex]\displaystyle P = \frac{F}{A}[/tex]

Solution:

[tex]\displaystyle P = \frac{1200 \ N}{0.1 \ m^2} \\\\P = 12,000 \ Pa\\\\\rule[225]{225}{2}[/tex]

promisecourage6

Answer:

P=3750

Explanation:

P=F/A

P=1200N/0.1m²

Find the square root of 0.1

square root of 0.1=0.316622776601

Approximate it =0.32

P=1200N/0.32M

Cross multiple=1200N=P0.32M

divide both side by

3750=P, P=3750

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