XoeyX695673 XoeyX695673
  • 03-11-2022
  • Mathematics
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5 Given the function below, find f(-4). * (2 Points) f (x) 22 + 3x-5 -10 39

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LadonO424282 LadonO424282
  • 03-11-2022

We have the function:

[tex]f(x)=2x^2+3x-5[/tex]

And we have to find f(4), this is the value of the function when x=4.

To do that we have to replace the x's in the equation by the value 4:

[tex]f(4)=2(4)^2+3(4)-5=2\cdot16+12-5=32+12-5=44-5=39[/tex]

The value of f(4) is 39.

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