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The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0. The equation of this circle in standard form is ____. The center of the circle is at the point____ , and its radius is_____ units.

Respuesta :

 = 7(x^2 + y^2 - 4x + 6y - 5)= 0

= 7( (x - 2)^2 - 4 + (y + 3)^2 - 9 - 5) = 0

=  7[ (x - 2)^2  + (y + 3)^2 - 18) = 0

center is at (2,-3) and radius = sqrt18  = 4.24 units
sofia50923

Answer:

A. (x - 2)^2 + (y + 3)^2 = 18.

B. (2, -3)

C. 3(2^(1/2))

Step-by-step explanation:

The equation of this circle in standard form is (x - 2)^2 + (y + 3)^2 = 18. The center of the circle is at the point (2, -3), and its radius is 3(2^(1/2)) units.

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