Pack21
Pack21
04-05-2018
Mathematics
contestada
The height of an object from a distance
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musiclover10045
musiclover10045
04-05-2018
y = height
x = distance from tower
tan(19.9) = y/x
tan(21.8) = y/(x-50) ( x is 50 feet closer so subtract 50 from x)
find the tan of the angles:
tan19.9 = 0.362
tan21.8 = 0.400
replace those values in the equations:
0.362 = y /x
0.400 = y / (x-50)
rewrite to solve for height:
0.362x = y
0.400(x-50) = y distribute the 0.400 and rewrite as 0.400x-20 =y
now solve:
0.362x = 0.400x-20
add 20 to each side:
0.362x +20 = 0.400x
subtract 0.362x from each side:
20 = 0.038x
divide both sides by 0.038
x = 20 / 0.038 = 526.3 feet
now that x is known replace x in the original equation and solve for y:
tan19.9 = y /x
0.362 = y / 526.3
y = 0.362 x 526.3
y = 190.5
the height of the tower is 190.5 feet
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